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4p^2-49=-21p
We move all terms to the left:
4p^2-49-(-21p)=0
We get rid of parentheses
4p^2+21p-49=0
a = 4; b = 21; c = -49;
Δ = b2-4ac
Δ = 212-4·4·(-49)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-35}{2*4}=\frac{-56}{8} =-7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+35}{2*4}=\frac{14}{8} =1+3/4 $
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